wap in c to find the total number of divisors of a given number.

#include<stdio.h>
#include<conio.h>
#include<math.h>
int arr[100000];
int prime(m,n)
{
int count;
long int i,j,t=1,a=1;
while(t--)
{
 if(m==1||m==2)
 arr[0]=2;
 if(m%2==0)
 m=m+1;
 for(i=m;i<=n;i=i+2)
   {
   count=0;
   for(j=3;j<=sqrt(i);j=j+2)
   if(i%j==0)
   {count++;break;}
  if(count==0&&i!=1)
   {arr[a]=i;
   a++;}
   }
}
return(0);
}
main()
{
int divisors=1,count=0,n,i=0,j;
printf("enter the number\n");
scanf("%d",&n);
prime(1,n);
while(n>1)
{
   {for(j=0;;j++)
    if(n%arr[i]==0)
     {n=n/arr[i];
      count++;}
    else
    {i++;break;}
     }
divisors=divisors*(count+1);
count=0;
}
printf("\nthe no of divisors is %d",divisors);
getch();

}

output